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NTA UGC NET COMPUTER SCIENCE 2020 Preperation
Tuesday, 2 June 2020
UGC NET Computer Science December 2019 | Question 18
Question 18
The sum of a number and its inverse is -4. The sum of their cubes is:
1.
-52
2.
52
3.
64
4.
-64
Explanation:
let x is a given number and consider that y is the inverse of x.
It is given that
x + y = - 4
∴ y = -4 - x
As, y is inverse of x
∴ x*y = xy = 1
Now sum of their cube
= x
3
+ y
3
by using formula: x
3
+y
3
=(x+y)
3
-3xy(x+y)
= (x+y)
3
- 3xy(x+y)
Now, replace (x+y) by -4
= (-4)
3
- 3xy (-4)
= -64 +12xy
Now, replace xy by 1
= -64+12
= -52
So, Option 1 is the right answer
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UGC NET CS December 2019 - Question 17
UGC NET CS December 2019 - Question 19
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It is given that
x + y = - 4
∴ y = -4 - x
As, y is inverse of x
∴ x*y = xy = 1
Now sum of their cube
= x3 + y3
by using formula: x3+y3=(x+y)3-3xy(x+y)
= (x+y)3 - 3xy(x+y)
Now, replace (x+y) by -4
= (-4)3 - 3xy (-4)
= -64 +12xy
Now, replace xy by 1
= -64+12
= -52
So, Option 1 is the right answer