UGC NET Computer Science July 2018 - II Question 42
Question 42
42. The period of a signal is 100 ms. Its frequency is _________.
(1) 1003 Hertz
(2) 10-2 KHz
(3) 10-3 KHz
(4) 1055 Hertz
Answer : (2) 10-2 KHz
Explanation Question 42
Frequency of signal= No of signals in a second
Here, period of one signal is given.
So, No of signal in 1 sec
= 1 sec/ period for one signal
= 1 / T
= frequency= 1/(100 ms) Here, we subtitute "ms" with "10-3" seconds
= (1/100*10-3)
= 1000/100
= 10 Hz
= (10*1000)/1000
= 10 KHz /1000
= 10-2 KHz
Frequency of signal= No of signals in a second
Here, period of one signal is given.
So, No of signal in 1 sec
= 1 sec/ period for one signal
= 1 / T
= frequency= 1/(100 ms) Here, we subtitute "ms" with "10-3" seconds
= (1/100*10-3)
= 1000/100
= 10 Hz
= (10*1000)/1000
= 10 KHz /1000
= 10-2 KHz