Monday, 1 April 2019

UGC NET Computer Science July 2018 - II Question 43

Question 43
The dotted-decimal notation of the following IPV4 address in binary notation is _________.   10000001 00001011 00001011 11101111

Options:
  1. (1) 111.56.45.239
  2. (2) 129.11.10.238
  3. (3) 129.11.11.239
  4. (4) 111.56.11.239
Answer : (3) 129.11.11.239
Explanation Question 43

In below table we convert all 4 bytes IPV4 address to the dotted-decimal notation.

Bit position
multiplication value(→)
1286432168421
4th byte10000001 = (128*1 + 1*1) = 129
3rd byte00001011 = (8*1+2*1+1*1) = 11
2nd byte00001011 = (8*1+2*1+1*1) = 11
1st byte11101111 = (128*1+64*1+32*1+8*1+4*1+2*1+1*1)
= 239

Hence, IPv4 address in dotted-decimal notation is 129.11.11.239

So, option (3) is correct answer

PreviousNext
UGC NET CS 2018 July - II Question 42UGC NET CS 2018 July - II Question 44

No comments:

Post a Comment

UGC NET Computer Science December 2019 | Question 16

Question 16 In a certain coding language. 'AEIOU' is written as 'TNHDZ'. Using the same coding language. 'BFJPV' wil...

Popular Posts