What is the least value of the function f(x) = 2x2-8x-3 in the interval [0,5] ?
(a) -15
(b) -7
(c) -11
(d) -3
Answer is (a),
f '(x) = 2x-8
Let f '(x) = 4x-8=0,
then, x=2,
substitute x=2 to the f ", but here no need to substitue in f ".
f ''(x) = 4 >0 (positive >> Minimum occurs at this point),
Refer this:
above question similar to Example 3 in below link:
https://www.math.wvu.edu/~hjlai/Words2Algebra/MinMax_Closed_Interva.pdf
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