Sunday 4 October 2020

UGC NET Exam Date 2020 Released. Check revised exam dates at Official Website ugcnet.nta.nic.in

University Grants Commission – National Eligibility Test (UGC-NET)

UGC NET 2020 Exam Dates Postponed for below subjects

  • Assamese, Malayalam, Marathi, Punjabi, Russian, Telugu, Bengali, Bodo, Kashmiri, Social Medicine & Community Health, Urdu postponed to date November 04, 2020
  • Computer Science, Sociology postponed to date November 11, 2020
  • Education, Geography postponed to date November 12, 2020
  • Hindi postponed to date November 13, 2020

NTA UGC NET Exam June 2020 revised date sheet announced, Admit card displayed at Official Website @ugcnet.nta.nic.in


(UGC-NET) : June 2020 Date Sheet of Examination

The UGC-NET June 2020 will be held as per following Schedule. Admit Cards for the examination to be held on 24.09.2020 and 25.09.2020 have been displayed. For others same shall be displayed on the NTA website soon.


NTA UGC NET 2020 Revised Exam Dates


Date Time Subject Code Subject Name Remark
September 24, 202009.00AM to 12.00 Noon (IST)46Adult Education/ Continuing Education/ Andragogy/ Non Formal Education.
32Chinese
62Comparative Study of Religions
33Dogri
44German
37Gujarati
50Indian Culture
45Japanese
21Kannada
85Konkani
18Maithili
35Manipuri
42Persian
91Prakrit
43Rajasthani
25Sanskrit
101Sindhi
40Spanish
70Tribal and Regional Language/Literature
03.00PM to 06.00PM (IST)49Arab Culture and Islamic Studies
29Arabic
60Buddhist, Jaina, Gandhian and Peace Studies
11Defence and Strategic Studies
31Linguistics
63Mass Communication and Journalism
34Nepali
23Oriya
83Pali
26Tamil
September 25, 202009.00AM to 12.00 Noon (IST)72Comparative Literature
68Criminology
71Folk Literature
82Forensic Science
39French (French Version)
66Museology & Conservation
4Psychology
93Tourism Administration and Management.
03.00PM to 06.00PM (IST)67Archaeology
92Human Rights and Duties
59Library and Information Science
3Philosophy
90Politics including International Relations/International Studies including Defence/Strategic Studies, West Asian Studies, South East Asian Studies, African Studies,South Asian Studies, Soviet Studies, American Studies.
September 29, 202009.00AM to 12.00 Noon (IST)58Law
47Physical Education
03.00PM to 06.00PM (IST)89Environmental Sciences
65Performing Art - Dance/Drama/Theatre
73Sanskrit traditional subjects (including) Jyotisha/Sidhanta Jyotish/ Navya Vyakarna/ Vyakarna/ Mimansa/ Navya Nyaya/ Sankhya Yoga/ Tulanatmaka Darsan/ Shukla Yajurveda/ Madhav Vedant/ Dharmasasta/ Sahitya/Puranotihasa /
95Santali
74Women Studies
September 30, 202009.00AM to 12.00 Noon (IST)17Management (including Business Admn. Mgt./Marketing/ Marketing Mgt./Industrial Relations and Personnel Mgt./Personnel Mgt./Financial Mgt./Co-operative Management)
September 30, 202003.00PM to 06.00PM (IST)1Economics / Rural Economics /Co-operation / Demography / Development Planning/ Development Studies / Econometrics/ Applied Economics/DevelopmentEco./Business Economics

October 1, 2020
09.00AM to 12.00 Noon (IST)030EnglishGroup-1
03.00PM to 06.00PM (IST)Group-2

October 9, 2020
09.00AM to 12.00 Noon (IST)6History
03.00PM to 06.00PM (IST)2Political Science

October 17, 2020
09.00AM to 12.00 Noon (IST)008CommerceGroup-1
03.00PM to 06.00PM (IST)Group-2

November 04, 2020(Old Date:22.10.2020)
09.00AM to 12.00 Noon (IST)36Assamese
22Malayalam
38Marathi
24Punjabi
41Russian
27Telugu
03.00PM to 06.00PM (IST)19Bengali
28Urdu
94Bodo
84Kashmiri
81Social Medicine & Community Health
November 5, 202009.00AM to 12.00 Noon (IST)88Electronic Science
55Labour Welfare/Personnel Management/Industrial Relations/ Labour and Social Welfare/Human Resource Management
16Music
15Population Studies
79Visual Art (including Drawing & Painting/Sculpture Graphics/Applied Art/History of Art)
03.00PM to 06.00PM (IST)7Anthropology
12Home Science
14Public Administration
10Social Work
100Yoga

November 11, 2020 (Old Date:07.10.2020)
09.00AM to 12.00 Noon (IST)5Sociology
03.00PM to 06.00PM (IST)87Computer Science and Applications

November 12, 2020 (Old Date : 21.10.2020)
09.00AM to 12.00 Noon (IST)9Education
03.00PM to 06.00PM (IST)80Geography
November 13, 2020 (Old Date:23.10.2020)09.00AM to 12.00 Noon (IST)020HindiGroup-1
03.00PM to 06.00PM (IST)Group-2

NTA UGC NET - June 2020 Exam Dates Postponed
(14th September, 2020 Public Notice) (Old Notice) :


This notice is regarding the postponed exam dates for NTA UGC NET - June 2020 Exam


National Testing Agency, NTA has released a notice informing that the UGC NET Exam 2020 has been postponed to be conducted now from September 24, 2020, onwards. The candidates who were to appear for the exam from September 16 must note that now the exams have been postponed by a week. The downloading of the admit card will soon be released on ugc.nta.nic.in.

Visit Official Website and check updates in section LATEST @ NTA with subject "Conduct of UGC- NET June Examination, 2020.":


Public Notice by NTA for UGC NET Examination (notice date: 14th September 2020)


National Testing Agency will be conducting ICAR Examination AIEEA-UG/PG and AICE-JRF/SRF (Ph.D.) 2020-21 on 16, 17, 22 and 23 September 2020. In view of ICAR Examination AIEEA-UG/PG and AICE-JRF/SRF (Ph.D.) 2020-21 being conducted on the above mentioned dates, UGC - NET 2020 Examination will now be held from 24th September onwards, this is due to some common candidates in both exams and the requests received thereof. The exact schedule of Subject-wise and Shift-wise details will be uploaded subsequently. The downloading of Admit Cards indicating Roll Number, Examination Centre, Date, Shift and timing of Examination will be announced shortly on the official website (ugcnet.nta.nic.in) of UGC- NET Examination, 2020.


Last Month updates
NTA Exam Dates 2020 Updates : Schedule for UGC NET Exam released at official website Auguest Updates from NTA NET regarding the Exam dates : Final date for UGC NET June exam announced on Thursday, 20 August, 2020.

Visit and check Exam date updates at UGC NET official website:

Public Notice by NTA for UGC NET Examination

UGC NET Exam date :
UGC - National Eligibility Test (UGC NET) June 2020 will be conducated in September on dates (16-18) Sep, 2020 and (21-25) Sep, 2020.

Downloading of Admit Cards:
The downloading of Admit Cards indicating Roll Number, Centre, Date, Shift and timing of Examination, will commence about 15 days before the date of examination on the respective official websites of these examinations

Thursday 1 October 2020

NTA UGC NET Computer Science | Graph Theory Questions Set 1 | Discrete Structures and Optimization

Question 1
The number of different spanning trees in complete graph, K4 and bipartite graph, K2,2 have ______ and _______ respectively.
  1. 1. 14, 14
  2. 2. 16, 14
  3. 3. 16, 4
  4. 4. 14, 4
Explanation Question 1

For any complete graph Kn with n nodes, different spanning trees possible is n(n-2)
So, spanning trees in complete graph K4 will be 4(4 - 2).
i.e. 42 = 16.

For any Bipartite graph Km,n with m and n nodes, different spanning trees possible is
m(n-1).n(m-1)

So, spanning trees in K2,2 will be 2(2-1) * 2(2-1).
i.e. 2 * 2 = 4.

So, option 3 is correct answer.

Question 2
A clique in a simple undirected graph is a complete subgraph that is not contained in any larger complete subgraph. How many cliques are there in the graph shown below?
  1. 1. 2
  2. 2. 4
  3. 3. 5
  4. 4. 6
Explanation Question 2

Total 5 clique will be there.
So, option (C) is correct.

Question 3
Which of the following statement(s) is/are false ?
(a) A connected multigraph has an Euler Circuit if and only if each of its vertices has even degree.
(b) A connected multigraph has an Euler Path but not an Euler Circuit if and only if it has exactly two vertices of odd degree.
(c) A complete graph (Kn) has a Hamilton Circuit whenever n ≥ 3.
(d)A cycle over six vertices (C6) is not a bipartite graph but a complete graph over 3 vertices is bipartite.
Codes:
  1. 1. (a) only
  2. 2. (b) and (c)
  3. 3. (c) only
  4. 4. (d) only
Explanation Question 3

A connected multigraph has an Euler Circuit if and only if each of its vertices has even degree.Correct A connected multigraph has an Euler Path but not an Euler Circuit if and only if it has exactly two vertices of odd degree.Correct A complete graph (Kn) has a Hamilton Circuit whenever n ≥ 3.CorrectA cycle over six vertices (C6) is not a bipartite graph but a complete graph over 3 vertices is bipartite.Incorrect
So, option (D) is cocrrect.

Question 4
Consider the graph given below:
The two distinct sets of vertices, which make the graph bipartite are:
  1. 1. (v1, v4, v6); (v2, v3, v5, v7, v8)
  2. 2. (v1, v7, v8); (v2, v3, v5, v6)
  3. 3. (v1, v4, v6, v7); (v2, v3, v5, v8)
  4. 4. (v1, v4, v6, v7, v8); (v2, v3, v5)
Explanation Question 4

A Bipartite Graph is a graph whose vertices can be divided into two independent sets, U and V such that every edge (u, v) either connects a vertex from U to V or a vertex from V to U. In other words, for every edge (u, v), either u belongs to U and v to V, or u belongs to V and v to U. We can also say that there is no edge that connects vertices of same set.
(v1, v4, v6, v7);
(v2, v3, v5, v8) is a bipartite graph vertices set.
So, option (C) is correct.

Question 5
A tree with n vertices is called graceful, if its vertices can be labelled with integers 1, 2,....n such that the absolute value of the difference of the labels of adjacent vertices are all different. Which of the following trees are graceful?

codes:
  1. 1. (a) and (b)
  2. 2. (b) and (c)
  3. 3. (a) and (c)
  4. 4. (a), (b) and (c)
Explanation Question 5

All given trees are graceful.
So, option (D) is correct.

Question 6
In the following graph, discovery time stamps and finishing time stamps of Depth First Search (DFS) are shown as x/y, where x is discovery time stamp and y is finishing time stamp. It shows which of the following depth first forest?
  1. 1. {a, b, e} {c, d, f, g, h}
  2. 2. {a, b, e} {c, d, h} {f, g}
  3. 3. {a, b, e} {f, g} {c, d} {h}
  4. 4. {a, b, c, d} {e, f, g} {h}
Explanation Question 6


Question 7
The inorder traversal of the following tree is:
  1. 1. 2 3 4 6 7 13 15 17 18 18 20
  2. 2. 20 18 18 17 15 13 7 6 4 3 2
  3. 3. 15 13 20 4 7 17 18 2 3 6 18
  4. 4. 2 4 3 13 7 6 15 17 20 18 18
Explanation Question 7

In inorder traversal first we traverse left node then root node and then right node: In the following tree we first go to the leftmost node then its root after that right i.e. 2 4 3 13 7 6 15 17 20 18 18. In rest of the option inorder property is violating. So, option (D) is correct.

Question 8
Consider the following statements:
(a) Depth - first search is used to traverse a rooted tree.
(b) Pre - order, Post-order and Inorder are used to list the vertices of an ordered rooted tree.
(c) Huffman's algorithm is used to find an optimal binary tree with given weights.
(d) Topological sorting provides a labelling such that the parents have larger labels than their children.
Which of the above statements are true?
  1. 1. (a) and (b)
  2. 2. (c) and (d)
  3. 3. (a), (b) and (c)
  4. 4. (a), (b), (c) and (d)
Explanation Question 8

Depth - first search is used to traverse a rooted tree. Correct Pre - order, Post-order and Inorder are used to list the vertices of an ordered rooted tree. CorrectHuffman's algorithm is used to find an optimal binary tree with given weights. CorrectTopological sorting provides a labelling such that the parents have larger labels than their children.Correct
So, option (D) is correct.

Question 9
Consider a Hamiltonian Graph (G) with no loops and parallel edges. Which of the following is true with respect to this Graph (G) ?
(a) deg (v) ≥ n / 2 for each vertex of G
(b) |E(G)| ≥ 1 / 2 (n - 1) (n - 2) + 2 edges
(c) deg (v) + deg (w) ≥ n for every n and v not connected by an edge.
  1. 1. (a) and (b)
  2. 2. (b) and (c)
  3. 3. (a) and (c)
  4. 4. (a), (b) and (c)
Explanation Question 9

In an Hamiltonian Graph (G) with no loops and parallel edges:
According to Dirac's theorem in a n vertex graph, deg (v) ≥ n / 2 for each vertex of G.
According to Ore's theorem deg (v) + deg (w) ≥ n for every n and v not connected by an edge is sufficient condition for a graph to be hamiltonian.
If |E(G)| ≥ 1 / 2 * [(n - 1) (n - 2)] then graph is connected but it doesn't guaranteed to be Hamiltonian Graph.
(a) and (c) is correct regarding to Hamiltonian Graph.
So, option (C) is correct.

Question 10
Consider the given graph

Its Minimum Cost Spanning Tree is __________.

(1)
(2)
(3)
(4)
  1. 1. (1)
  2. 2. (2)
  3. 3. (3)
  4. 4. (4)
Explanation Question 10

A minimum spanning tree (MST) or minimum weight spanning tree for a weighted, connected and undirected graph is a spanning tree with weight less than or equal to the weight of every other spanning tree.
In option (A) weight of tree is = 103 but it is not the subgraph from graph because in original graph there is no edge between node(6) and (7).
In option (B) weight of tree is = 99
In option (C) weight of tree is = 127
In option (D) weight of tree is = 106
So, option (B) is correct.

UGC NET Computer Science December 2019 | Question 16

Question 16 In a certain coding language. 'AEIOU' is written as 'TNHDZ'. Using the same coding language. 'BFJPV' wil...

Popular Posts