UGC NET Computer Science July 2018 - II Question 50

Question 50

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Encrypt the Message “HELLO MY DEARZ” using Transposition Cipher with

Key

{

Plain Text    2 4 1 3 Cipher Text    1 2 3 4

Options:

1. (1) HLLEO YM AEDRZ
2. (2) EHOLL ZYM RAED
3. (3) ELHL MDOY AZER
4. (4) ELHL DOMY ZAER

Answer: (3) ELHL MDOY AZER

Explanation Question 50

Given:
In question encryption of given message using Transposition Cipher with Given message is “HELLO MY DEARZ”
Key - Plain Text -> 2 4 1 3
Key - Cipher Text ->1 2 3 4

Solution:
Step-1: According to key size divide number of character into blocks. Here, key size is 4. So, character block size is 4.
Step-2: Remove the spaces in the given message and write characters in sequential order. Now arrange then in group of 4 as shown in below matrix.

Key
1	2	3	4
H	E	L	L
O	M	Y	D
E	A	R	Z

Step-3: Sort column as per given Plain key as shown in below matrix.

Key
2	4	1	3
E	L	H	L
M	D	O	Y
A	Z	E	R

Read the matrix horizontally one by one row.

Encrypted message will be ELHL MDOY AZER.

So, option (3) is correct.

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UGC NET CS 2018 July - II Question 49	UGC NET CS 2018 July - II Question 51