Monday 1 April 2019

UGC NET CS 2018 July - II Question 95

Question 95
95. The hexadecimal equivalent of the binary integer number 110101101 is :
  1. (1) D24
  2. (2) 1BD
  3. (3) 1AE
  4. (4) 1AD
Answer : (3) 1AE

Explanation Question 95

Answer: 3

Group the given number in subgroup of 4 from right and assign alphabet when it exceeds 1001:
1010 – A
1011 – B
1100 – C
1101 – D
1110 – E
1111 – F
Given number is 110101101:
1101 – D
1010 – A
1 – 1

Hexadecimal equivalent iss 1AD.
So, option (D) is correct.


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