Question 1
1. An organization has a Class B Network and need to form subnet for 64 departments
what would be the appropriate Subnet Mask
what would be the appropriate Subnet Mask
Question 2
2. Consider a class A, Class B and Class C network.
Consider the given IP address and subnet mask
IP Address : 150.157.100.70
Subnet Mask : 255.255.224.0
What is the address of the network in which host belong to
Consider the given IP address and subnet mask
IP Address : 150.157.100.70
Subnet Mask : 255.255.224.0
What is the address of the network in which host belong to
Explanation Question 2
If any given IP address performs bit wise AND operation with the subnet mask, then you get the network id of the subnet to which the given IP belongs.
If IP address = 150.157.100.70 (convert it into binary form)
Binary form of IP address is : 10010110.10011101.01100100.01000110
Binary form of network address is : 10010110.10011101.01100000.00000000
Deciaml form of network address is : 150.157.96.0
Therefore, Nid = 150.157.96.0
So, option (2) is the correct answer.
If any given IP address performs bit wise AND operation with the subnet mask, then you get the network id of the subnet to which the given IP belongs.
If IP address = 150.157.100.70 (convert it into binary form)
Binary form of IP address is : 10010110.10011101.01100100.01000110
IP address | = 10010110.10011101.01100100.01000110 |
Subnet mask | = 11111111. 11111111. 11100000.00000000 |
Bit Wise AND | = 10010110.10011101.01100000.00000000 |
Binary form of network address is : 10010110.10011101.01100000.00000000
Deciaml form of network address is : 150.157.96.0
Therefore, Nid = 150.157.96.0
So, option (2) is the correct answer.
Question 3
3. Subnet mask for a particular network is 255.255.31.0 then tell about Which pairs of IP addresses could belong to this network ?
Explanation Question 3
If IP1 and IP2 belongs to same network, we must have
IP1 BITWISE-AND "Subnet mask" = Network Address
= IP2 BITWISE-AND "Subnet mask"
Out of the 4 options, only option D matches.
128.8.129.43 BITWISE-AND 255.255.31.0 = 128.8.1.0
128.8.161.55 BITWISE-AND 255.255.31.0 = 128.8.1.0
Both addresses belongs to same network.
You can check rest of the options.
If IP1 and IP2 belongs to same network, we must have
IP1 BITWISE-AND "Subnet mask" = Network Address
= IP2 BITWISE-AND "Subnet mask"
Out of the 4 options, only option D matches.
128.8.129.43 BITWISE-AND 255.255.31.0 = 128.8.1.0
128.8.161.55 BITWISE-AND 255.255.31.0 = 128.8.1.0
Both addresses belongs to same network.
You can check rest of the options.
Question 4
4. If a class B IP address has the subnet mask 255.255.248.0 then How many maximum host will be possible in the network?
Explanation Question 4
Binary form of subnet mask of 255.255.248.0 is : 11111111.11111111.11111000.00000000 From above binary form of subnet mask. you can say that subnet mask of 255.255.248.0 will have a 21 bits network id and having 11 host bits.
Given the subnet mask, you can calculate the number of hosts using the formula below:
2h - 2, where h is the number of host bits (in simple terms the number of zeros in the subnet mask)
This network will have total 2048 (211 ) hosts. The first address is the network address, while the last one is the broadcast ip address, thus we subtract 2 addresses, then there can be a maximum 2046 hosts.
So, option (3) is the correct answer.
Binary form of subnet mask of 255.255.248.0 is : 11111111.11111111.11111000.00000000 From above binary form of subnet mask. you can say that subnet mask of 255.255.248.0 will have a 21 bits network id and having 11 host bits.
Given the subnet mask, you can calculate the number of hosts using the formula below:
2h - 2, where h is the number of host bits (in simple terms the number of zeros in the subnet mask)
This network will have total 2048 (211 ) hosts. The first address is the network address, while the last one is the broadcast ip address, thus we subtract 2 addresses, then there can be a maximum 2046 hosts.
So, option (3) is the correct answer.
Question 5
5. If a Class B IP address is split into subnet and 6 bits are used for subnet. What is maximum number of subnet and hosts per subnet ?
Explanation Question 5
3
3
Question 6
6. Consider the IP address 25.193.155.233. How many bits are there in Network Id and Host Id ?
Explanation Question 6
2
2
Question 7
7. Find the wrong statement among the following related to Subnetting?
Explanation Question 7
3
3
Question 8
8. Logical addressing system is used by which device ?
Explanation Question 8
4
4
Question 9
9. Which of the following is not true about Supernetting?
Explanation Question 9
1
1
Question 10
10. What is the network ID of the IP address 225.100.123.71?
Explanation Question 10
4
4
In class B network, 16 bits are used for Network ID and 16 bits are for Host ID part. In subnetting the bits are borrowed from Host portion.
Here, we want 64 subnets. so, we have to borrow 6 bits from host id part because 26 = 64 number of subnets we require. Subnet mask will have total 16 + 6 bits as continuous 1's. in network id and subnet id part.
Binary form of subnet mask is : 11111111.11111111.11111100.00000000
Decimal form of subnet mask is : 255.255.252.0
So, option (4) is the correct answer.