UGC NET Computer Science July 2018 - II Question 42

Question 42

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42. The period of a signal is 100 ms. Its frequency is _________.

1. (1) 100³ Hertz
2. (2) 10^-2 KHz
3. (3) 10^-3 KHz
4. (4) 105⁵ Hertz

Answer : (2) 10^-2 KHz

Explanation Question 42

Frequency of signal= No of signals in a second
Here, period of one signal is given.
So, No of signal in 1 sec
= 1 sec/ period for one signal
= 1 / T
= frequency= 1/(100 ms)    Here, we subtitute "ms" with "10^-3" seconds
= (1/100*10^-3)
= 1000/100
= 10 Hz
= (10*1000)/1000
= 10 KHz /1000
= 10^-2 KHz

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