Question 83
83. You are designed a link layer protocol for a link with bandwidth of 1 Gbps (109 bits/second) over a fiber link with length of 800 km. Assume the speed of light in this medium is 200000 km/second. What is the propagation delay in this link?
Answer : 4. 4 millisecond Previous | Next |
UGC NET CS 2018 July - II Question 82 | UGC NET CS 2018 July - II Question 84 |
Given data:
Fiber link length = distance = 800 km.
Speed of light in this medium = velocity = 200000 km/second
and we know that 1 sec is equel to 1000 milliseconds
Solution:
Propagation delay : Time taken by the first bit to travel from sender to receiver end of the link.
Propagation delay = distance/transmission speed
Propagation delay
= 800km / ( 200000km /sec)
= ( 800 / 200000) sec
= ( 800 / 200 ) milliseconds
= 4 ms
So, option 4 is correct answer