Question 102
Let A = {001,0011,11,101} and B= {01,111,111,010}. Similarly.
let C = {00,001.1000} and D = {0,11,011}.
Which of the following pairs have a post-correspondence solution?
Answer : 1. Only pair (A, B) let C = {00,001.1000} and D = {0,11,011}.
Which of the following pairs have a post-correspondence solution?
Question 102 Explanation
Before solving this question, let understand what is PCP problem.
The Post Correspondence Problem is to determine whether a collection of dominos has a match.
Given the following two lists, M and N of non-empty strings over ∑
M = (x1, x2, x3,………, xn)
N = (y1, y2, y3,………, yn)
We can say that there is a Post Correspondence Solution, if for some i1,i2,..... ik, where 1 ≤ ij ≤ n, the condition xi1 …….xik = yi1 …….yik satisfies.
Given data is :
A
B
C
D
Now, A convenient way to view an instance of a Post correspondence problem is as a collection of blocks of the form
there being an unlimited supply of each type of block. Thus the given example is viewed as
A, B have a PCP solution because
A3A4A1 = 11 . 101 . 001 = 11101001 = 111. 010 . 01 = B2B1B1
Furthermore, since (3, 4, 1) is a solution, so are all of its "repetitions", such as (3, 4, 1, 3, 4, 1), etc.; that is, when a solution exists, there are infinitely many solutions of this repetitive kind.
So, option 1 is correct answer
Reference : Post correspondence problem example
Before solving this question, let understand what is PCP problem.
The Post Correspondence Problem is to determine whether a collection of dominos has a match.
Given the following two lists, M and N of non-empty strings over ∑
M = (x1, x2, x3,………, xn)
N = (y1, y2, y3,………, yn)
We can say that there is a Post Correspondence Solution, if for some i1,i2,..... ik, where 1 ≤ ij ≤ n, the condition xi1 …….xik = yi1 …….yik satisfies.
Given data is :
A
A1 | A2 | A3 | A4 |
001 | 0011 | 11 | 101 |
B
B1 | B2 | B3 | B4 |
01 | 111 | 111 | 010 |
C
C1 | C2 | C3 |
00 | 001 | 1000 |
D
D1 | D2 | D3 |
0 | 11 | 011 |
Now, A convenient way to view an instance of a Post correspondence problem is as a collection of blocks of the form
Ai |
Bi |
there being an unlimited supply of each type of block. Thus the given example is viewed as
A1 | A2 | A3 | A4 |
001 | 0011 | 11 | 101 |
B1 | B2 | B3 | B4 |
01 | 111 | 111 | 010 |
A, B have a PCP solution because
A3A4A1 = 11 . 101 . 001 = 11101001 = 111. 010 . 01 = B2B1B1
Furthermore, since (3, 4, 1) is a solution, so are all of its "repetitions", such as (3, 4, 1, 3, 4, 1), etc.; that is, when a solution exists, there are infinitely many solutions of this repetitive kind.
So, option 1 is correct answer
Reference : Post correspondence problem example
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