UGC NET Computer Science December 2019 | Question 136

Question 136

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An instruction is stored at location 500 with its address field at location 501. The address field has the value 400. A processor register R₁ contains the number 200. Match the addressing mode (List-I) given below with effective address (List-II) for the given instruction:

Match List-I with List-II :

List I	List II
a. Direct	i. 200
b. Register indirect	ii. 902
c. Index with R1 as the index register	iii. 400
d. Relative	iv. 600

1. 1. (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
2. 2. (a)-(i), (b)-(ii)), (c)-(iii), (d)-(iv)
3. 3. (a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)
4. 4. (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)

Answer : 1. (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)

Explanation Question 136

				Main Memory
Instruction			500	Opcode	Mode
Opcode	500	→	501
			502	Next Instruction
			⋮
	R1	200	⋮
			⋮ ⋮

Direct Address = 400
Relative Address = Next Instruction memory location + Direct Address value
= 502 + 400
= 902

Register indirect Address= 200
Indexed Address = Register Indirect Address + Direct Address
= 200 + 400
= 600

So, option 1 is correct answer

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