UGC NET Computer Science December 2019 | Question 80

Question 80

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Given CPU time slice of 2ms and following list of processes.

Process	Bursttime (ms)	Arrival time
P1	3	0
P2	4	2
P3	5	5

Find average turnaround time and average waiting time using round robin CPU scheduling?

1. 1. 4, 0
2. 2. 5.66, 1.66
3. 3. 5.66, 0
4. 4. 7, 2

Answer : 2. 5.66, 1.66

Explanation

Given data:
CPU time slice = 2 ms
Sheduling Algorithm : Round Robin CPU scheduling

Gantt Chart:

P1	P2	P1	P2	P3	P3	P3
0	2	4	5	7	9	11	12

Process	Bursttime (ms)	Arrival time	Completion time	Turn around time	Watiting time
P1	3	0	5	5	2
P2	4	2	7	5	1
P3	5	5	12	7	2

Average Turnaround Time
= ( 5 + 5 + 7 ) / 3
= 5.66

Average Waiting Time
= ( 2 + 1 + 2 ) / 3
= 1.66

So, option 2 is correct answer.

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